Prove that the value of the expression: b (36^5−6^9)(38^9−38^8) is divisible by 30 and 37.

(30)(37)(-6⁷)(38⁸)

Step-by-step explanation:

(36⁴−6⁹)(38⁹−38⁸)

(36⁴ - 6⁹) = (6²)⁴ - 6⁹

= 6⁸ - 6⁹

= 6⁷(6 - 6²)

= 6⁷(6 - 36)

= 6⁷(-30)

(38⁹ - 38⁸)

= 38⁸(38 - 1)

= 38⁸(37)

36⁴−6⁹)(38⁹−38⁸)

6⁷(-30) × 38⁸(37)

(30)(37)(-6⁷)(38⁸)

Clearly 30 and 37 are factors, so divisible by them

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

answer: apothems is your answer

step-by-step explanation: hope u get it right