There are 7 cherries and 3 grapes in a bag. What is the pobability of selecting 2 grapes at random without replacement?

1/15

Step-by-step explanation:

7+3 = 10 items in the bag

P(grape) = grapes/total

                3/10

No replacement

7 cherries 2 grapes = 9 items

P(grape) =  grapes/total

                    2/9

P(grape, no replacement, grape) = 3/10*2/9

                                                       =1/15

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632