All that is left in a packet of candy are 5 reds, 5 greens, and 4 blues.
(a)What is the probability that a random drawing yields a blue followed by a red assuming that the first candy drawn is put back into the packet?

5/49

Step-by-step explanation:

There are a total of 14 candies.

The probability the first candy is blue is 4/14.

Since the candy is replaced, there are still a total of 14 candies.  So the probability the second candy is red is 5/14.

Therefore, the probability of both is 4/14 × 5/14 = 20/196 = 5/49.

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5