In a certain Algebra 2 class of 21 students, 6 of them play basketball and 14 of them play baseball. There are 5 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Step-by-step explanation:

5 of them play neither sport.

We can subtract 5 from 21 to get the kids that play a sport.

16-(14+6), is -4.

so 4 is the number of kids that play both sports.

so the probability is 4/21.

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p