If x increased by the product of 11 and y is 103, and 9x increased by the product of 10 and y is 126, what are the values of x and y?
A. x= 8y=5
B. x = 9.y = 12
C. X= 4, y = 9
D. x = 9, y = 4

C. x=4,y=9

Step-by-step explanation:

The given information show that

x+11y=103 (1)

9x+10y=126 (2)

Isolate x from (1)

x=103-11y

Substitute x=103-11y into (2)

9(103-11y)+10y=126

927-99y+10y=126

-89y=-801

y=9

So x=103-11x9=4

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00