How do I solve the question the width of a rectangle is six meters more less than it's length. If the area of the rectangle is 112m squared find the dimensions of the rectangle

The dimensions of the rectangle is 14m by 8m

The formula for calculating the area of a rectangle is expressed as:

A = LW

L is the length

W is the width

If the width of a rectangle is six meters less than its length, then;

W = L - 6

Substitute into the expression

A = L(L-6)

112 = L^2 - 6L

L^2 - 6L - 112 = 0

On factorizing, the value of L is 14 and -8

Recall that W = L - 6

W = 14 - 6

W = 8

Hence the dimensions of the rectangle is 14m by 8m

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Length of rectangle = 14 meters

width of rectangle = 8 meters

Step-by-step explanation:

Let the length of rectangle be x meters

width of the triangle is (x - 6) meters

Area of the rectangle is Length x width

112m² = x * (x -6)

112 = x² - 6x

x² - 6x - 112 = 0

x² - 14x +  8x - 112 = 0

x (x - 14) + 8 ( x - 14) = 0

(x - 14)(x + 8) = 0

x - 14 = 0                                     x + 8 = 0

x = 14                                           x = -8

width can't be negative value

Therefore,

Length of rectangle = 14 meters

width of rectangle = 14 - 6 meters

                              = 8 meters

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60