Franklin rolls a pair of six-sided fair dice with sides numbered 1 through 6.
The probability that the sum of the numbers rolled is either even or a multiple of 5 is
The probability that the sum of the numbers rolled is either a multiple of 3 or 4 is

11/18

5/9

Step-by-step explanation:

Make a table showing all the possible sums for two dice:

Of the 36 possible sums, 18 are even, 7 are multiples of 5, and 3 are both even and multiple of 5.  So the probability is:

P(even or multiple of 5) = (18 + 7 − 3) / 36 = 22/36 = 11/18

Of the 36 possible sums, 12 are multiples of 3, 9 are multiples of 4, and 1 is a multiple of both 3 and 4.  So the probability is:

P(multiple of 3 or 4) = (12 + 9 − 1) / 36 = 20/36 = 5/9

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus