How do I solve this problem using the substitution method
x-3y=4
4x-2y=26

x=7

y=1

Step-by-step explanation:

In order to use substitution you need to get one of the equations to have a variable by itself. I'm going to use the first one and get x by itself.

x-3y= 4  So firstly add the 3y to both sides since you want x alone.

 +3y  +3y

x=3y+4

Now that you have x alone you can plug this into the second equation for x.

4(3y+4)-2y=26

Next distribute the 4 to both terms inside the parenthesis.

4(3y)+4(4)-2y=26    Simplify.

12y+16-2y=26         Now add or subtract your like terms together (12y-2y).

10y+16=26              Next subtract 16 from both sides.

     -16  -16

10y=10                   Finally, to get y alone divide by 10 on both side.

y=1

To find x you plug y back into one of the equations you started with. I'm using x-3y=4  Again.

x-3(1)=4        Distribute the -3 to the one.

x-3=4           Now add 3 to both sides.

+3 +3

x=7

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine