A family has two cars during one particular week the first car consume 25 gallons of gas and the second consumed 15 gallons of gas the two cars Drove a combined total of 1075 miles and the sum of the fuel efficiencies was 55 miles per gallon what were the fuel efficiencies of each of the cars that week?

the efficiency of the first car is 25 miles per gallon.

the efficiency of the second car is 30 miles per gallon.

Step-by-step explanation:

Let x represent the efficiency of the first car.

Let y represent the efficiency of the second car.

Distance = car efficiency × number of gallons.

The first car consume 25 gallons of gas and the second consumed 15 gallons of gas. The two cars Drove a combined total of 1075 miles. It means that

25x + 15y = 1075- - - - - - - - - - -1

The sum of the fuel efficiencies was 55 miles per gallon. It means that

x + y = 55

Substituting x = 55 - y into equation 1, it becomes

25(55 - y) + 15y = 1075

1375 - 25y + 15y = 1075

- 25y + 15y = 1075 - 1375

- 10y = - 300

y = - 300/-10

y = 30

x = 55 - y = 55 - 30

x = 25

can you rephrase the question ? it is unclear : -)

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560