A fish in an aquarium with flat sides looks out at a hungry cat. To the fish, the distance to the cat appears to be A fish in an aquarium with flat sides looks out at a hungry cat. To the fish, the distance to the cat appears to be Equal to the actual distance. Less than the actual distance. More than the actual distance.

Hence A fish in an aquarium see the cat more than actual distance.

Step-by-step explanation:

Given:

A fish in aquarium with flat silde looks out to cat .

To find :

Appearance of fish to the cat.

Solution:

Now this problem is related to the refractive index of 2 mediums

So cat is  in air medium and a fish in water i.e. aquarium

R.I of water =1.33

R.I of air =1.00

We know the incident ray ,reflected ray,refracted ray and normal .

When a incident ray enter in denser medium it bends towards  normal.

But it diverges outward direction and goes beyond the actual object.

(Refer the Attachment).

Hence A fish in an aquarium see the cat more than actual distance.

d i think

step-by-step explanation: