Can someone help me find x please

You can use the pythagoras’ theorem and just look at one right triangle.
The dimensions for one of the right triangles is (x/2), 8, and square root of 80.

a^2 + b^c = c^2
when c is the square root of 80.

Plug everything in
(x/2)^2 + 8^2 = (square root of 80)^2

That is equivalent to
((x^2)/4) + 64 = 80

Solve for x
((x^2)/4) = 16

Multiple by 4 on each side
x^2 = 64

Take the square root and you have you’re final answer
x = 8

Where is the problems