A parabola opens to the left. which could be the equation of the parabola
(x-4)^2=4(y+3)
(x-4)^2=-4(y+3)
(y-4)^2=4(x+3)
(y-4)^2=-4(x+3)

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!

The correct answer is b

2x + 3y = 114x + 2y = - 2 ( original equation x -1)4x + 6y = 22 ( original equation x 2)- 4x + 2y = - 2= 4y = 24÷4y = 62x + 18 = 11-182x = - 7÷2x = - 3.5

Ithink the answer is d