In a thunderstorm, the wind velocity in meters per second can be described by the function v(p) = 5.7 √998 - p, where p is the air pressure in millibars. What is the air pressure of a thunderstorm in which the wind velocity is 49.3 meters per second?

923.1927 millibars

Step-by-step explanation:

The wind velocity is given by the function:

#We make p the subject of the formula:

#Substitute the given values in the function above to solve for p;

Hence, the air pressure is 923.1927 millibars.

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35