A statistics professor finds that when she schedules an office hour for student help, an average of 2.4 students arrive. find the probability that in a randomly selected office hour, the number of student arrivals is 2

P=0.2613

Step-by-step explanation:

-Notice that this is a poison probability distribution problem.

-The Poisson probability function is expressed as:

where:

Given that x= 2 and , the probability is calculated as:

Hence, the  probability that in a randomly selected office hour, the number of student arrivals is 2 is 0.2613

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5