Mathematics, 04.04.2020 01:59 edirsonperez3073

What is the diameter of a circle with the equation (x + 6)2 + (y − 4)2 = 16?

A) 4
B) 8
C) 16
D) 32

Answers: 2

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Answers

Answer from: mikurrjurdan

The diameter of the circle is 8, which is mentioned in option B, if a circle equation is $(x+6)^{2}+(y-4)^{2} = 16$ .

Step-by-step explanation:

The given is,

Circle equation is $(x+6)^{2}+(y-4)^{2} = 16$ .

Step:1

Equation for circle is,

$(x-h)^{2}+(y-k)^{2} = r^{2}$ .......................(1)

Where,

(h, k) - Center point

r - Radius of circle

Given equation,

$(x-h)^{2}+(y-k)^{2} = r^{2}$ ....................(2)

Comparing equation (1) and equation (2)

(h, k) - (-6, 4)

$r^{2}$ - 16

Take square root on both side,

$r = \sqrt{16}$

r = 4

Formula for diameter,

d = 2r

=(2)(4)

= 8

Diameter of circle, d = 8

Result:

The diameter of the circle is 8, which is mentioned in option B, if a circle equation is $(x+6)^{2}+(y-4)^{2} = 16$ .

Answer from: Quest

answer:

125 yards

explanation:

75+50=125. that is my answer

Answer from: Quest

answer: no

step-by-step explanation: because the big angle will spread away the 2 side that it is on and make the opposite side even longer.

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What is the diameter of a circle with the equation (x + 6)2 + (y − 4)2 = 16?

A) 4
...

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