One freshman, 2 sophomores, 4 juniors, and 5 seniors receive top scores in a school essay contest. To choose which 2 students will read their essays at the town fair; 2 names are chosen from a hat. What is the probability that a junior and then a senior are chosen?

5/33

Step-by-step explanation:

The total number of names in the hat is 1+2+4+5 = 12

P(junior) = # juniors/ total = 4/12 = 1/3

Then we remove the name so there are 11 names in the hat

One freshman, 2 sophomores, 3 juniors, and 5 seniors

P(2nd name is senior) = # seniors/ total = 5/11

P( junior,then senior no replacement) = 1/3 * 5/11

                                                       = 5/33

5/33 oe 0.1515

Step-by-step explanation:

Total = 1 + 2 + 4 + 5 = 12

4/12 × 5/11 = 5/33

= 0.1515151515

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step-by-step explanation:

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a