A rectangular lot is 110 yard long and 60 yards wide. Give the length and width of another rectangular lot that has the same perimeter but larger area.

Length and width of 85 yards will give the same perimeter and larger area.

Step-by-step explanation:

Let x represent length and y represent width of rectangle.

The perimeter of the rectangle would be .

We have been given that a rectangular lot is 110 yard long and 60 yards wide. The perimeter of the given rectangle would be 2 times the width and length.

Upon equating both perimeters, we will get:

Divide both sides by 2:

We know that area of rectangle is length times width.

Now, we will take the derivative of area function as:

Now we will equate derivative with 0 and solve for x.

Therefore, the length of rectangle would be 85 yards.

Upon substituting in equation , we will get:

Therefore, the width of rectangle would be 85 yards.

This means that we will get a square. Since each square is a rectangle, therefore, length and width of 85 yards will give the same perimeter and larger area.

We can verify our answers.

huh? im pretty sure it is in 199

step-by-step explanation:

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