Some fireworks are fired vertically into the air from the ground at an initial speed of 80 feet for second. The equation for this object’s height h at time t seconds after launch is h = -16t^2 + 80t. How long will it take the fireworks to reach the ground ?

answer: 590

step-by-step explanation:

it is b)

hope this : )

step-by-step explanation:

false

step-by-step explanation:

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.