Please help

Write the standard equation of a circle that passes through (−5, 5) with center (−10, −5).

A: (x – 10)2^+ (y – 5)2^= 75

B: (x + 10)2^+ (y + 5)2^= 125

C: (x + 10)2^+ (y + 5)2^= 75

D: (x – 10)2^+ (y – 5)2^= 125

Correct  B: (x + 10)² + (y + 5)² = 125

Step-by-step explanation:

Given:

Point A(-5, 5)   point that belong to the circle

Point C(-10, -5) = (a, b)   coordinates of the center of the circle

The standard form of the circle equation is:

(x - a)² + (y - b)² = r²

we will replace the given coordinates in the circle equation

(-5 -(-10))² + (5 -(- 5))² =  r²

(-5 + 10)² + (5 + 5)² =  r²

5² + 10² = 125 = r²

r² = 125

the required equation of the circle is:

(x + 10)² + (y + 5)² = 125

God is with you!!!

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.