Airlines overbook flights so that no-shows do not cost the airline lost revenue. Suppose an airline estimates its average number of unoccupied seats per flight over the last 12 months by randomly selecting records from 225 flights. The mean unoccupied seats per flight is 11.6 with variance of 16.81 timate the mean number of unoccupied seats per flight for the past 12 months using a 90% confidence interval. So what? a) Es

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

a.)the line for function b is steeper

the first option i believe

step-by-step explanation:

p

step-by-step explanation: