If AH = 8 mm, A F = 17 mm, and FC = 41 mm, what would be the distance between A and D? Round your answers to two decimal places. (had to put a bunch of spaces between a and f cuz wouldnt allow it lol

AD = 27.29

Step-by-step explanation:

Notice that you can use similar triangles to solve this problem.

The small triangle on the top right (AFH) is similar to the triangle ACD.

So you can use that the ratio between corresponding sides must be equal.

Notice also that the side AC has length = 17 mm + 41 mm = 58 mm

You can set then the following proportion:

in decimal form, this can be rounded to: 27.29

19.29 mm

Step-by-step explanation:

AH/AD = A F/AC

8/AD = 17/(41+17)

AD = 8 × 58/17

AD = 27.2941176472

HD = AD - AH

= 27.2941176472 - 8

= 19.2941176471

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

step-by-step explanation: