When you graph a system of two linear equations, which outcome is NOT possible?
A. The lines do not intersect, so there are no solutions.
B. The lines intersect at one point, so the system has one solution.
C. The lines intersect in two different points, so the system has two solutions.
D. The graphs of the two equations are the same line, so there are infinitely many solutions.

A. The lines do not intersect, so there are no solutions.

This is true, if the line's never intersect and don't have a common/same point, there are no solutions.

B. The lines intersect at one point, so the system has one solution.

This is true because they have 1 same point so they have 1 solution

C. The lines intersect in two different points, so the system has two solutions.

This is not possible, straight lines can only intersect 1 time. If the lines are curved, then they can intersect more than once

D. The graphs of the two equations are the same line, so there are infinitely many solutions.

This is true because they will always have the same points, so they will have an infinite number of solutions

figure c

step-by-step explanation:

hope this .

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~