A password must have 2 letters and 3 digits. How many different passwords are possible?
pls explain :)

There are, you see, 3 x 2 x 1 = 6 possible ways of arranging the three digits. Therefore in that set of 720 possibilities, each unique combination of three digits is represented 6 times. So we just divide by 6. 720 / 6 = 120.

Step-by-step explanation:

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

a

step-by-step explanation: