Trapezoid ABCD has vertices A(1,6) B(-2,6) C(-10,-10) and D(20,-10). Find the measure of ABCD’s midsegment to the nearest tenth

16.5 units

Step-by-step explanation:

The midsegment is the distance between the midpoints of the nonparallel sides of the trapezoid.

The trapezoid ABCD has vertices A(1,6) B(-2,6) C(-10,-10) and D(20,-10).

We want to find the midsegment of ABCD to the nearest tenth.

The midpoint of BC is;

The midpoint of AD is :

The length of the midsegment is the distance from (-6,2) to (10.5,2)

answer is 144

step-by-step explanation: