How many different 4-question geometry quizzes can a teacher make
if there are 7 different problems to test on?

Hint: combination
• 38 quizzes
•35 quizzes
• 14 quizzes
• 28 quizzes

A teacher can make 35 quizzes.

Step-by-step explanation:

Given that,

Total problems = n = 7

Number of questions in a quiz = r = 4

We need to find the ways in which different 4-question geometry quizzes can a teacher make  if there are 7 different problems to test.

For that, the combination is used: nCr =

By putting the values, we get

35 quizzes

Hence, a teacher can make 35 quizzes.  

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w