Find the equivalent expression
12a + 6b

a. 6(2a + b)
b. 6(6a + b}
c. 2(6a + 4b)
d. 2(10b + 4b)

6(2a+b)

Step-by-step explanation:

We are to factorise the given question

Which means we will have to determine what is common to both numbers

12a+6b

We can deduce that 6 is common to both

So let's factorise

6(2a+b)

Therefore the final answer is 6(2a+b)

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.