Find the volume of a right circular cone that has a height of 12 m and a base with a diameter of 8.9 m. Round your answer to the nearest tenth of a cubic meter.

Volume of Cone

Volume of the right circular cone is  248.7 m³

Step-by-step explanation:

A right circular cone is a three dimensional geometrical object. Right circular cone is a circular cone whose axis is perpendicular to its base. The slant height is the length of an element. All elements of a right circular cone  are all equal.

The volume of the right circular cone is defined as  

where r is radius of the cone and h is the height of the cone

V =  

Given diameter d  = 8.9 m

So the radius r = 8.9 ÷ 2 = 4.45 m

V = (1/3) × 3.14 × (4.45)²  × 12

= (1/3) × 3.14 × 19.80 × 12

= 248.69 m³

Hence the Volume of the right circular cone is  248.7 m³

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.