Determine the discriminant for the quadratic equation 0 = –2x2 3. based on the discriminant value, how many real number solutions does the equation have?
discriminant = b2 – 4ac

If you would like to know the discriminant of the quadratic equation 0 = -2x^2 + 3, you can do this using the following steps:

0 = -2x^2 + 3

0 = ax^2 + bx + c
a = -2, b = 0, c = 3

D = b^2 - 4 * a * c = 0^2 - 4 * (-2) * 3 = 0 + 4 * 2 * 3 = 24

The discriminant is 24 (positive).

If the discriminant of a quadratic equation is equal to zero (b^2 - 4ac = 0), there is one real root which is repeated. If the discriminant is positive (b^2 - 4ac > 0), there are two real roots; and if the discriminant is negative (b^2 - 4ac < 0), there are two complex roots.

Therefore, the equation has 2 real roots.

it's

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: