A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.
Click "Show Your Work" and write a quadratic function, h(t), that shows
the height, in feet, of the soccer ball, t seconds after it was kicked. Use
the general equation h(t) = -16t2 + v0t + h0 where v0 is the initial velocity
and h0 is the initial height.

h(t) = - 16t² + 96t

Step-by-step explanation:

A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.

So, it initial height, ft. and initial velocity feet/sec.

Now, the quadratic function, h(t), that shows the height, in feet, of the soccer ball, t seconds after it was kicked will be given by the general equation

⇒ h(t) = - 16t² + 96t + 0

⇒ h(t) = - 16t² + 96t (Answer)

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14