What is the slope of the line that passes through the points (-2, 3) and (-14, -5)

Slope = 2/3

Step-by-step explanation:

The equation of the line

y = mx + c

y = intercept point y

m = slope of the line

x = intercept point x

c = intercept of the line

The slope of the line

m = y2 - y1 / x2 - x1

Given

( -2 , 3) ( -14 , -5)

x1 = -2

y1 = 3

x2 = -14

y2 = -5

Insert the values

m = -5 - 3 / -14 - (-2)

= -8 / -14 + 2.

= -8 / -12

Minus cancels minus

= 8/12

Divide by 4

m = 2/3

The slope of the line is 2/3

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180