A town sits at point (5,1) on a map. From the tallest building in the town, you can see objects up to 7 miles away. If each unit on the map is equivalent to 1 mile, you can see a statue in a town at point (2,5)? Explain.

The distance between the tallest building and the statue is 5 miles, so as the statue is inside the range of 7 miles, it can be seen from the tallest building.

Step-by-step explanation:

To solve the problem we need to know the distance between the tallest building in the town and the statue.

This distance can be calculated with the formula of the distance between two points:

d = sqrt(dx^2 + dy^2), where dx is the difference in x-coordinate between the points and dy is the difference in y-coordinate between the points.

So, the distance between these points is:

dx = 5-2 = 3

dy = 1-5 = -4

d = sqrt(3^2 + (-4)^2) = sqrt(9+16) = 5 miles

The distance is 5 miles, so as it is inside the range of 7 miles, the statue can be seen from this point.

step-by-step explanation:

no solution.

27 +27 or 27times 2=54

the diffrence is 0