Which function's graph has a period of 2?

Option 2. y = 3 cos πx is the answer.

Step-by-step explanation:

If the function is in the standard form of y = acos(bx+c)  or y = asin(bx+c)

Then period of the given function will be = 2π/b

1) For y = cos(x - π/2)

Therefore period of the function will be = 2π/1 = 2π

2) For y = 3cos πx

Period = 2π/π = 2

Correct option.

3) y = 2 sin 3x

Period of the function = 2π/3

4). y = -4sin 2x

Period of the function = 2π/2 = π

So option 2 is the answer.

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step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).