Help me with another math question

x = 3

y = -1

( 3, -1 )

Step-by-step explanation:

5x + 2y = 13

 3x - y = 10

Multiply "3x - y = 10 " by 2

5x + 2y = 13

6x - 2y = 20

Cancel out +2y and -2y

11x = 33

Divide both sides by 11

x = 3

 3(3) - y = 10

     9 - y = 10

         -y = 1

          y = -1

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.