Suppose that 30% of a population carries a certain gene. You want to estimate the probability that it will take at least a sample of
four to find a person that carries the gene, how could you simulate a person having or not having the gene?
0, 1, 2 could represent a person that carries the gene, and 3, 4, 5, 6, 7, 8,9
could represent a person that does not carry the gene.
0, 1, 2, 3 could represent a person that carries the gene, and 4, 5, 6, 7, 8, 9
could represent a person that does not carry the gene.
0, 1, 2 could represent a person that does not carry the gene, and 3, 4, 5, 6,
7,8,9 could represent a person that carries the gene
0,1,2, 3 could represent a person that does not carry the gene, and 4, 5, 6,
7,8,9 could represent a person that carries the gene.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

we'll this would mean that the dunk tank and the bounce house are the same for 20 hours because the 2 represents that the two activities, and the 20 represents the amount of hours they both are. so with this said, it means that the answer is c. the costs for a dunk tank and bounce house are the same for 20 hours.

c.the costs for a dunk tank and bounce house are the same for 20 hours.

hope this .

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

i would be happy to . most people on would also love to i'm sure. if you just want someone who has done algebra before and want a little more personal relationship than just begging strangers for , i can certainly be of service. i do have college myself so i might not be 24/7.