If f and g are functions of time, and at time t = 2, f equals 5 and is rising at a rate of 6 units per second, and g equals 7 and is rising at a rate of 9 units per second, then f/g equals and is changing at a rate of units per second. If f and g are functions of time, and at time t = 3, f equals 9 and is rising at a rate of 6 units per second, and g equals 8 and is rising at a rate of 9 units per second, then f/g equals and is changing at a rate of units per second.

a)

It is changing at a rate of  units per seconds

b)

It is changing at a rate of units per seconds

Step-by-step explanation:

A

Given that:

f and g are functions of time (t):

i.e  

f(t) =0

g(t) = 0

Now; at time (t) = 2 ; f equals 5 and is rising at a rate of 6 units per second.

Also; at time 2; g equals 7 and is rising at a rate of 9 units per second

This implies that:

f(2) = 5                   f' (2) = 6

g(2) = 7                  g' (2) = 9

Then can be directly  calculated from the  given values which is:

Using differentiation to determine the rate of changing ; we have

=

∴ It is changing at a rate of  units per seconds

B

Given that:

f and g are functions of time (t):

i.e  

f(t) =0

g(t) = 0

NOW; at time (t) = 3

f (3) = 9                                      f' (3) = 6

g (3) = 8                                     g' (3) = 9

Then can be directly  calculated from the  given values which is:

Using differentiation to determine the rate of changing ; we have

∴ It is changing at a rate of units per seconds

The negative signs means they are decreasing.

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.