Find the zeros of the function f(x)=x^2+2x-15 explain how this process could be used to solve for the solutions the quadratic equation x^2+2x-15=0

PLEAS ANSWER SOOONN

3  , -5

Step-by-step explanation:

hello :

f(x)=x²+2x-15

compliting squard  :  f(x)=(x²+2x+1) - 1-15

f(x) = (x+1)²-16

f(x) = 0 means :  (x+1)²-4² =0

by identity : a²-b² =(a-b)(a+b)a=x+1  and  b= 4

(x+1-4)(x+1+4) = 0

(x-3)(x+5)=0

x-3=0  or x+5=0    so : x=3  or x= -5

the zeros of the function f(x)=x^2+2x-15 are : 3  , -5

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

answer:

a=9

step-by-step explanation: lmk if you need a explanation