Jason plans to invest $9,000 in an account at Union Bank. The annual rate is 3.78% compounded

countinously. How much does Jason have at the end of 10 years?

$13 042.8

Step-by-step explanation:

We will simply use the formula;

Amount = p [ 1 + R/100]^t

Where p = principal amount

R = Rate

and T=time given in year

From the question given;

principal(p)= $9000

Rate(r) =3.78

Time(t) = 10

We can now proceed to inert the values into the formula;

Amount = p [ 1 + R/100]^t

              =$9000 [1 + 3.78/100]^10

                = $9000[1 + 0.0378]^10

                  =$9000[1.0378]^10

                  =$9000×1.4492

                   =$13 042.8

Therefore, at the end of 10 years, Jason will have $13 042.8

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step-by-step explanation:

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