A triangular flag is 4 times as long as its width. A rectangular mat is 14 feet longer than its width. Both the flag and the mat have an area of 72 square feet. Find the base and height of the flag

For the triangle: length = 24ft, width = 6ft.

For the rectangular mat: length = 18ft, width = 4ft.

Step-by-step explanation:

A triangular flag is 4 times as long as its width, meaning

,

and the area of the this flag is 72 square feet, which means

solving for width we get:

which gives a length of

Similarly, rectangular mat is 14 feet longer than its width, meaning

and its area is 72 square feet which means

simplification gives

which we solve using the quadratic formula to give

,

,

and since the width cannot be a negative number, we choose as our answer.

Thus, the length of the rectangular box is

To summarize, the length and the width of the triangular flag is 24 and 6 feet respectively, and for the rectangular box it is 18 and 4 feet respectively.

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.