Substitute each equation by multiplication.
6x-2y=-6
-2x-3y=2

x = -1

y = 0

Step-by-step explanation:

to solve the equation by substitution in order to  evaluate for x and y

let

6x-2y=-6   equation 1

-2x-3y=2 equation2

from equation 2

-2x-3y=2 equation2

-2x -2 = 3y

divide both sides by 3

(-2x -2)/3 = y

y = (-2x -2)/3 equation3

substitute y = (-2x -2)/3 into equation 1

6x-2y=-6   equation 1

6x - 2[  (-2x -2)/3]  = -6

6x  + (4x + 4)/ 3 = -6

multiply through by 3

18x + 4x + 4 = -18

22x = -18-4

22x = -22

divide both sides by the coefficient of x which is 22

22x/22 = -22/22

x = -1

substitute for x in equation 3

y = (-2x -2)/3 equation3

y = -2(-1) - 2/3

y = 2 -2/3

y = 0/3

y = 0

therefore the value of x and y is -1 and 0 respectively

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons