A1100- car is held in place by a light cable on a very smooth (frictionless) ramp, as shown in the figure (figure 1) . the cable makes an angle of 31.0 above the surface of the ramp, and the ramp itself rises at 25.0 above the horizontal.

So far i have determined the following equations from the my force body diagrams. T(cos(31)) - mg(sin(25)) = 0 N - (mg(cos(25)) + (T(sin(31))) = 0 to solve for tension you rearrange the first equation to get T(cos(31)) = mg(sin(25)) so if you solve for the horizontal component of gravity you will be able to determine the tension of the string. i have tried my following answer (which comes out to 1426N) but i am incorrect. if anyone can please point out what i am missing i would be really appreciate it.

fsfd

step-by-step explanation:

fdddff

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column