A circular path 2 feet wide has an inner diameter of 950 feet. How much farther is it around the outer
edge of the path than around the inner edge? Round to nearest hundredth. Use 3.14 for it.
The outer edge of the path is
feet farther around than the inner edge.

12.56 feet

Step-by-step explanation:

Given: The width of the circular path= 2 feet

The inner diameter of circular path= 150 feet

Therefore, the inner radius of circular path=

Now, the outer radius= 75+2=77 feet

We know that the circumference=

Inner circumference=

Outer circumference=

The difference=

Hence, the outer edge of the path is 12.56 feet farther than the inner edge

last one.

step-by-step explanation:

last one.

generally speaking, the others follow some sort of pattern that correlates to either linear (looks like a straight line) or sinusoidal (looks like an s).

the last one is just a random cloud of points that doesn't correlate to any particular known order.

step-by-step explanation: 4 cause 2+2=4