Joey is buying plants for his gardenHe wants to have at least twice as many flowering plants as nonflowering plants and a minimum of 36 plants in his gardenFlowering plants sell for $8, and nonflowering plants sell for $5Joey wants to purchase a combination of plants that minimizes costLet x represent the number of flowering plants and y represent the number of nonflowering plants.

What are the vertices of the feasible region for this problem?

The vertices of Feasible region are .

Step-by-step explanation:

Given that,

He wants to have at least twice as many flowering plants as nonflowering plants.

Let  number of flowering plants be .

and number of non-flowering plant be .  

According to question,

Inequality form by from given situation is :

                                                              ..............(1)

 And Minimum number of flowers should in Garden must be represented by the Inequality is :

                                                       .................(2)

Cost of x flowering plants be  .

Cost of y nonflowering plants be

Also, he has to minimize the cost then Inequality will be  

                Minimum cost  

Now,

The feasible solution are one who satisfy the constraints (1) & (2).

So, Solving Constraints (1) & (2) we get

putting the value of equation (1) in equation (2)

then                            

Again Solving Equation (1) & (1) we get, &

Hence,

The vertices of Feasible region are .

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180