The given line passes through the points -4, - 3 and 4, 1 what is the equation in point-slope form of the line that is perpendicular to the given line and passes through the point -4,3

y - 3 = -2(x + 4)

Step-by-step explanation:

Point slope form: y - y1 = m(x - x1)

Slope equation from two points: y2-y1/x2-x1

The first step is to find the slope of the perpendicular line. Use the slope equation from above.

1 - (-3)/4 - (-4)

4/8

1/2

The slope of the line with the points (-4, -3) and (4, 1) is 1/2. To find the perpendicular slope, find the opposite reciprocal of 1/2. The answer is -2.

Now that you have a point and a slope, you can plug the values in to the point slope form equation from above.

y - 3 = -2(x + 4)

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b