Soup ordinarily priced at 2 cans for .33 cents may be purchased in lots of one dozen for 1.74, what is the savings per a can when it is purchased in this way

The savings per a can when it is purchased in this way is $0.02 per can.

Cost of can when purchased ordinarily:

Cost of can =.33/2

Cost of can=.165 per can

Cost of can when purchased in lot:

Cost of can 1.74/12

Cost of can=.145 per can

Savings per can:

Savings per can=.165-.145

Savings per can=$.02 per can

Inconclusion the savings per a can when it is purchased in this way is $0.02 per can.

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Savings per can would be 0.02 cents when purchased in lots.

Step-by-step explanation:

Given:

Ordinary price of soup 2 cans = 0.33 cents.

When purchases in lots 12 cans = 1.74

We need to find the saving per can when purchased in Lots.

Solution:

Ordinary price of soup 2 cans = 0.33 cents.

1 can  = Cost of 1 can when purchased ordinary.

By Using Unitary method we get;

Cost of 1 can when purchased ordinary =

Now we will find the Cost of 1 can when purchased in lot.

12 cans = 1.74

1 can = Cost of 1 can when purchase in lot.

Again by using Unitary method we get;

Cost of 1 can when purchase in lot =

Savings = Cost of 1 can when purchase in lot - Cost of 1 can when purchased ordinary

Savings =

Hence Savings per can would be 0.02 cents when purchased in lots.

you have to find the same variables -3n - 5n so this would be -3n +(-5n) which equals -9n