Decide whether the relation defines a function.

{(-8, 2), (-8, 8), (1, 4), (6, -4), (10, 2)}

A. Function

B. Not a function

B

Step-by-step explanation:

When given an ordered pair in defining a function, we have to note that each x value pairs up with a unique y value. If there is more than 1 y-value for any x-value, this would NOT be a function.

If there is ordered pair as shown below:

(2, 7), (4, 5), (-2, 3), (2, 7)

We can think that there are two 2's and this isn't a function, but wait!

2 pairs with 7 and the next one, 2 also pairs with 7, so it is a function, eventhough it is written twice. They are the same.

Now, looking at the ordered pair given in this problem:

{(-8, 2), (-8, 8), (1, 4), (6, -4), (10, 2)}

-8 is paired with "2"

as well

-8 is paired with "8"

So, there are "2" y-values for a single value of x, -8

So, it is not a function

Correct answer is B

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

idc

step-by-step explanation:

idk