A sample of 56 randomly selected cellphones of a new model were checked for a particular defect. Of these, 38 of the cellphones were found to be defective. Find a 80% confidence interval for p. Use the Agresti-Coull method.

Confidence Interval: (0.60, 0.76)

Step-by-step explanation:

The provided information is:

Sample Size (n) = 56

Consider X be the number of defective cellphones. Then X = 38

Proportion of defective cellphones is:

At 80% confidence interval, value of z is 1.28

Thus, the 80% confidence interval for proportion is given as:

y-1700=200(x+4)

step-by-step explanation:

200(x+4) is 200x + 800 she is saving 200 per week x is the weeks and the -1700 is. us that’s howmuch she already had