General Electric manufactures a decorative Crystal Clear 60-watt light bulb. Suppose that the lifetimes of the light bulbs are approximately normally distributed, with a mean of 1550 hours and a standard deviation of 57 hours. What would be the cutoff value for a light bulb that lasts in the top 10% of all bulbs

The lifetime of bulb should be 1623.074 hours or more to lie in the top 10%.        

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1550 hours

Standard Deviation, σ =  57 hours

We are given that the distribution of lifetimes of the light bulbs is a bell shaped distribution that is a normal distribution.

Formula:

We have to find the value of x such that the probability is 0.10

Calculation the value from standard normal z table, we have,  

Thus, the lifetime of bulb should be 1623.074 hours or more to lie in the top 10%.

answer: -2+√x,-2-√x

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