The base of a triangle is shrinking at a rate of 11 cm/s and the height of the triangle is increasing at a rate of 11 cm/s. Find the rate at which the area of the triangle changes when the height is 10cm and the base is 8cm.

the rate of changes  of the area of the triangle

Step-by-step explanation:

Explanation :-

The area of triangle( A) =    ..........(1)

Let 'b' be the base and 'l' be the length of the triangle

The base of a triangle is shrinking( means decreasing) at a rate of 11 cm/s

that is

The height of a triangle is increasing at a rate of 11 cm/s

that is

Given h= 10cm and b = 8cm

The rate of change of triangle

applying uv formula  

Differentiating equation (1) with respective to 't'

substitute all values in above equation, we get

h= 10cm , b = 8cm , and

After simplification , we get

answer: .75 km

step-by-step explanation:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: