In the function f(x) = (x - 2)^2 + 4, the minimum occurs at

4

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

The max/ min of the function is the value of k

f(x) = (x - 2)² + 4 ← is in vertex form

with (h, k) = (2, 4 ) → k = 4

Thus minimum occurs at 4

probably .5

i can on others if necessary.

25/6 hope it : )

step-by-step explanation: