An equilateral triangular plate with sides 4 m is submerged vertically in water so that the base is even with the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it. (Round your answer to the nearest whole number. Use 9.8 m/s2 for the acceleration due to gravity. Recall that the weight density of water is 1000 kg/m3.)

The Hydrostatic force is =7800N

Step-by-step explanation:

Let recall the following,

The hydrostatic force is a force that occurs when a force resulting from pressure of a body or fluid at rest

The hydrostatic force is the pressure at the center x the area

The Pressure is = density x gravity x height

The acceleration due to gravity = 9.8m^2

The weight of the water (density) = 1000 kg/m3

So find the mass at the center which is,

√(4)/2 that is below the water level

The hydrostatic force is = (√(4)/2m) (1000 kg/m^3 x 9.8m/s) ((1/2)(4)(4√(4)/2)m^2)

Therefore, in expressing the hydrostatic force against one side of the plate is.

(√(4)/2m) (1000 kg/m^3 x 9.8m/s) ((1/2)(4)(4√(4)/2)m^2) =7800N

The Hydrostatic force =7800N

answer: 26

step-by-step explanation:

well, michelle wanted to measure the height of her school's flagpole she placed a mirror on the ground 48 feet from the flagpole then walk backwards until she was able to see the top of the pole in the mirror her eyes were 5 feet above the ground and she was 12 ft from the mirror using similar triangles find the height of the flagpole to the nearest tenth of a foot find the geometric mean of them pair of numbers. its easy math

two data sets with the same median will not have the same varaibility

step-by-step explanation: